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发表于 2018-9-5 17:05:25
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本帖最后由 marmot@tj 于 2018-9-5 17:16 编辑
- Room {
- id = "city/xidajie1",
- name = "西大街",
- ways = {
- ["south"] = "city/zhubaodian",
- ["east"] = "city/xidajie2",
- ["north"] = "city/jiulou",
- ["west"] = "city/ximen",
- },
- nolooks = {
- ["north"] = true,
- ["south"] = true,
- },
- lengths = {
- ["north"] = "if MidDay[locl.time] then return false else return 1 end",
- ["south"] = "if MidDay[locl.time] then return false else return 1 end",
- },
- }
复制代码
看这个就知道珠宝店开不开门
另外你可以在check_food()或者check_job()的时候建个触发器检查首饰的数量或名称或id。发现数量不足或是哪个不见了(相应变量没有被赋值)再判断时间决定要不要去找回
如果是用名称或id查找的话,记得每次检查前要重置成 nil 数量的话要重置成0 不然下次检查就会出问题的 |
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