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楼主 |
发表于 2023-7-15 17:19:48
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只做送信1 songxin.lua
function songxin2_consider()
EnableTriggerGroup("songxin2_killer",true)
--if sxjob.sx2==0 then return Sx2toTdh() end
--do return songxin2_refuse() end
if sxjob.sx2==0 then return sx2overok() end
if job.time.over<35 then return songxin2_refuse() end
--if not flag.sx2 and sxjob.sx2==1 then return songxin2_refuse() end
if job.zuhe["hubiao"] and (not condition.hubiao or condition.hubiao==0) then
return sx2overok()
end
if score.party and score.party~='普通百姓' then
messageShow('送信任务2:只做送信1')
return songxin2_refuse()
end |
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