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主要思路:使用空属性憋合气,放sword.lian杀武士。
基于无法风的公版mush机器人和ru版的绕指设置。
条件:不需要灵器 不需要神兵 只需要一把剑 ,需要1000级太极剑,不需要定制版。
补充:有左右互搏会加快积累合气速度,根骨高能站得住,武器好能杀得动。
缺点:sword.raozhi的释放不是最优,多数情况是用的空属性放swod.lian。
- kezhi_valueraozhi={
- ["正"]='妙',
- ["刚"]='快',
- ["妙"]='奇',
- ["快"]='柔',
- ["险"]='正',
- ["慢"]='刚',
- ["奇"]='险',
- ["无"]='妙',
- ["空"]='空',
- ["柔"]='险',--120克制
- }
- function wudangRaozhi(targetsx)
- raozhi_sx=kezhi_valueraozhi[targetsx]
- if raozhi_sx and score.party and score.party=='武当派' then
- create_trigger_t('fightraozhi1',"^[> ]*你施展出太极剑法中的绕指柔剑,剑势陡然变(\\D*)手中\\D*",'','raozhibegin')
- create_trigger_t('fightraozhi2',"^[> ]*你剑意一滞,又恢复到原来的攻势",'','raozhiend')
- SetTriggerOption("fightraozhi1","group","afight")
- SetTriggerOption("fightraozhi2","group","afight")
- if job~=nil and job.name ~= nil and job.name =='songmoya' then
- if heqi == nil or heqi <640 then
- Send('alias pfmraozhi set 绕指 空;perform sword.raozhi')
- else
- if raozhi_sx=='慢' then
- Send('alias pfmraozhi unset 绕指;perform sword.raozhi')
- else
- Send('alias pfmraozhi set 绕指 '..raozhi_sx..';perform sword.raozhi')
- end
- end
- else
- if raozhi_sx=='慢' then
- Send('alias pfmraozhi unset 绕指;perform sword.raozhi')
- else
- Send('alias pfmraozhi set 绕指 '..raozhi_sx..';perform sword.raozhi')
- end
- end
- end
- end
- function raozhibegin(n,l,w)
- Send('alias pfmraozhi')
- end
- function raozhiend()
- print('绕指结束')
- if raozhi_sx then
- if job~=nil and job.name ~= nil and job.name =='songmoya' then
- if heqi == nil or heqi <640 then
- Send('alias pfmraozhi set 绕指 空;perform sword.raozhi')
- else
- if raozhi_sx=='慢' then
- Send('alias pfmraozhi unset 绕指;perform sword.raozhi')
- else
- Send('alias pfmraozhi set 绕指 '..raozhi_sx..';perform sword.raozhi')
- end
- end
- else
- if raozhi_sx=='慢' then
- Send('alias pfmraozhi unset 绕指;perform sword.raozhi')
- else
- Send('alias pfmraozhi set 绕指 '..raozhi_sx..';perform sword.raozhi')
- end
- end
- end
- end
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